Correct Answer - The 30th term of the given A.P. is 148
Here, `a= t_(1) = 3, t_(2) =8, t_(3) = 13, t_(4) = 18,….`
`:. D= t_(2) - t_(1) = 8 - 3 = 5 `
Let the nth term of the A.P. be 148. (So `t_(n) = 148`)
`:. T_(n) = a+ ( n -1) d ` ..(Formula )
`:. 148 = 3+ ( n -1) xx(5)` …(Substituting the values )
`:. 148 = 3 + 5n -5 ` `:. 148 = 5n - 2 ` `:. 5n = 148 +2` `:. 5n = 150`
`:. n = ( 50)/( 5)` `:. n = 30`