Question

For what value of n, the nth terms of the arithmetic progressions 63, 65, 67, … and 3, 10, 17,… are equal?

Answer 1

Correct Answer - n= 13
`T_(n) = t_(n) rArr 63 + (n-1) xx 2 = 3 + (n-1) xx 7 rArr 5n = 65 rArr n = 13.`