**For tin can with rectangular 6 base. **

l = 5 cm, b = 4 cm, h = 15 cm

Volume of the tin can = lbh = 5 × 4 × 15 cm^{3} = 300 cm^{3}

For plastic cylinder with circular base.

r = 7/ 2 cm = 3.5 cm, h = 10 cm

Volume of the plastic cylinder = π r^{2}h

= 22/ 7 × 3.5 × 3.5 × 10 cm^{3} = 385 cm^{3 }

Difference in the capacities of the two containers

= (385 – 300) cm^{3 }= 85 cm^{3}

Hence, the plastic cylinder with circular base has greater capacity by 85 cm^{3}** Ans.**