Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
121 views
in Linear Equations by (44.9k points)
closed by
On selling a tea-set 5% loss and a lemon-set at 15% gain, a crockery seller gains Rs. 7. If he sells the tea-set at 5% gain and the lemon-set at 10% gain, he gains Rs. 13. Find the actual price of the tea-set and the lemon-set.

1 Answer

0 votes
by (43.8k points)
selected by
 
Best answer
Let the cost price of the tea-set and 15% gain on lemon-set
Loss on tea-set = Rs. `(5x)/(100)`
Gain on lemon-set = Rs `(15y)/(100)`
But net gain = Rs. 7
implies `(15y)/(100) - (5x)/(100) = 7 implies 15y - 5x = 700 implies -x + 3y = 140 " ...(1)"`
Case II : When 5% gain on tea-set and 10% gain on lemon-set
Gain on tea-set = Rs. `(5x)/(100)`
Gain on lemon-set = Rs. `(10 y)/(100)`
But net gain = Rs. 13
implies `(5x)/(100) + (10y)/(100) = 13 implies 5x + 10y = 1300 implies x + 2y = 260 " ...(2)"`
Adding equations (1) and (2), we get
5y = 400 implies y = 80
Putting y = 80 in equation (1), we get
x = 3 (80) - 140 = 100
`therefore` Cost of tea-set = Rs. 100 and the cost of lemon-set = Rs. 80

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...