Here, h = 14 cm.

Radius of the pencil (R) = 7/ 2 mm = 0.35 cm.

Radius of the graphite (r) = 1/ 2 mm = 0.05 cm.

Volume of the the graphite = π r^{2}h

= 22/ 7 × 0.05 × 0.05 × 14 cm^{3} = 0.11 cm^{3}

Volume of the the wood = π (R^{2} – r^{2})h

= 22/ 7 × [(0.35)^{2} – (0.05)^{2}] × 14 cm^{3}

= 22/ 7 × 0.4 × 0.3 × 14 cm^{3 }= 5.28 cm^{3}

Hence, volume of the wood = 5.28 cm^{3 }and volume of the graphite

**= 0.11 cm**^{3 }Ans