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If `cos theta = (2)/(3), " write the value of " ((sectheta-1))/((sectheta+1)).`

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If `cos theta = (2)/(3), " write the value of " ((sectheta-1))/((sectheta+1)).`
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Correct Answer - `(1)/(5)`
`((sectheta-1))/(sectheta +1)=(((3)/(2)-1))/(((3)/(2)+1))=((1)/(2)xx(2)/(5))=(1)/(5).`
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