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If `cottheta=1/(sqrt(3))` , show that `(1-cos^2theta)/(2-sin^2theta)=3/5`

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Correct Answer - `(3)/(5)`
`((1-cos^(2)theta))/((2-sin^(2)theta))=(sin^(2)theta)/((2-sin^(2)theta))=((3)/(4))/((2-(3)/(4)))" "["cosec"^(2)theta=(1+cot^(2)theta)=(1+(1)/(3))=(4)/(3) rArr sin^(2)theta=(3)/(4)]`
`=((3)/(4)xx(4)/(5))=(3)/(5).`

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