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If `cos e c theta=2x` and `cottheta=2/x` , find the value of `2(x^2-1/(x^2))`

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If `cos e c theta=2x` and `cottheta=2/x` , find the value of `2(x^2-1/(x^2))`
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Correct Answer - `(1)/(2)`
Squaring and subtracting, we get
`4(x^(2)-(1)/(x^(2)))=("cosec"^(2)theta-cot^(2)theta)=1rArr2(x^(2)-(1)/(x^(2)))=(1)/(2).`
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