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Without using trigonometric tables , evaluate the following :
`(cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot40^(@))/(tan50^(@))-(cos^(2)20+cos^(2)70^(@))`

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Correct Answer - B
Given expression`=(tan theta*costheta)/(sintheta)+(cot40^(@))/(tan(90^(@)-40^(@)))-{cos^(2)20^(@)+cos^(2)(90^(@)-20^(@))}`
`=(sintheta)/(costheta)*(costheta)/(sintheta)+(cot40^(@))/(cot40^(@))-{cos^(2)20^(@)+sin^(2)20^(@)}=1+1-1=1.`

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