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If `tantheta=a/b` then find the value of `(costheta+sintheta)/(costheta-sintheta)`
A. `(a+b)/(a-b)`
B. `(a-b)/(a+b)`
C. `(b+a)/(b-a)`
D. `(b-a)/(b+a)`

1 Answer

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Correct Answer - C
`((costheta+sintheta))/((costheta-sintheta))=((1+tantheta))/((1-tantheta)) " " ["dividing num. and denom. by "costheta]`
`=((1+(a)/(b)))/((1-(a)/(b)))=((b+a))/((b-a)).`

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