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In the formula `bar(x)=a+h(sumf_(i)u_(i))/(sumf_(i))`
for finding the mean of grouped frequency distribution `u_(i)` is equal to
A. `((A-x_i))/h`
B. `((x_i-A))/h`
C. `((A+x_i))/h`
D. `h(x_i-A)`

1 Answer

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Best answer
We have `u_i=((x_i-A))/h`

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