# Find two consecutive positive integers sum of whose squares is 365.

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Find two consecutive positive integers sum of whose squares is 365.

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Let two consecutive positive integers be x and x+1
" " therefore x^(2) + (x+1)^(2) = 365
rArr x^(2) + x- 182=0
" " (x + 14) (x - 13)=0
" " therefore x = 13
Hence two consecutive positive integers are 13 and 14