Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
138 views
in Chemistry by (71.9k points)
closed by
Write the molecular formulae of the thired and fifth memebers of homologous eries of carbon compounds represented by the general formula `C_(n)H_(2n-2)`.

1 Answer

0 votes
by (72.1k points)
selected by
 
Best answer
The general formula `C_(n)H_(2n-2)` is of the alkyne series . We know that the first member of the alkyne series is ethyne `(C_(2)H_(2))` and it has 2 carbon atoms in its molecule.
(i) Since the first member of alkyne series has 2 carbon atopmes in the therefore, third member of alyne series will have 4 carbn atoms in its molecule . Soif wer put n=4 in the general formula `C_(n)H_(2n-2)` then the molecular formula of the fifth memeber of the alkyne series will be `c_(6)H_(2)xx6-2 "or" C_(6)H_(10)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...