Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.6k views
in Chemistry by (56.2k points)

For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w = – nRT ln Vf/V 

A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversibly to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct option. 

(i) Work done at 600 K is 20 times the work done at 300 K. 

(ii) Work done at 300 K is twice the work done at 600 K. 

(iii) Work done at 600 K is twice the work done at 300 K. 

(iv) ΔU = 0 in both cases.

1 Answer

+1 vote
by (78.5k points)
selected by
 
Best answer

(iii) Work done at 600 K is twice the work done at 300 K. 

(iv) ΔU = 0 in both cases.

since temperature is constant this means there is no change in internal energy.

Therefore, ΔU = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...