Required area = (area of 2 quarter circles with radius 5 cm) `+` (area of 2 semicircles with radius 2 cm) `+` (area of two equilateral triangles) `+` (area of trapezium)
`2 xx pi (5)^(2) xx (90^(@))/(360^(@)) + 2 xx (1)/(2) xx pi (2)^(2) + 2 xx (1)^(2) (sqrt3)/(4) + (1)/(2) xx 1.5 (1 + 3)`
`= (25 pi)/(2) + 4 pi + (sqrt3)/(2) + 3`
`= (33 xx 3.14)/(2) + (1.732)/(2) + 3`
`= 51.81 + 0.866 + 3`
`= 55.676 cm^(2)`