Given, length of wiper blade = 25 cm = r (say)
Angle made by this blade, `theta = 115^(@)`
`:.` The area cleaned by one blade = Area of sector formed by blade
`= (theta pi r^(2))/(360^(@)) = 115^(@) xx (22)/(7 xx 360^(@)) xx (25)^(2) = (23 xx 22)/(7 xx 72) xx 625`
`= (23 xx 11 xx 625)/(7 xx 36) = (158125)/(252) cm^(2)`
`:.` Total area cleaned by both blade `= 2 xx` the area cleaned by one blade
`= (2 xx 158125)/(252) = (158125)/(126) cm^(2)`