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If `DeltaABC` is right angled at `C`, then the value of `cos(A+B)` is

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Correct Answer - A
We know that, in `DeltaABC`, sum of three angles =`180^(@)`
i.e., `angleA + angleB + angleC=180^(@)`
But right angled at C i.e., `angleC=90^(@)` (given)
`angleA + angleB + 90^(@)=180^(@)`
`rArr A+B=90^(@)` `[therefore angleA=A]`
`therefore` cos(A+B)`=cos90^(@)=0`
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