(i). Option : (d)
Fuel cost= k(speed)2
⇒ 48 = k.162
⇒ k = \(\frac{3}{16}\)
(ii) Option : (b)
Let the total cost of running train is C.
According to the question,
\(\frac{dC}{at}=\frac{3}{16}v^2+1200\)
\(\Rightarrow C=\frac{3}{16}v^2t+1200t\) (By integrating both sides w.r.t t)
Hence, total cost of running train is \(C=\frac{3}{16}\nu^2t+1200t\)
Distance covered = 500km
\(\Rightarrow\) time \(=\frac{500}{\nu}hrs\)
Total cost of running train 500 km \(=\frac{3}{16}\nu^2\left(\frac{500}{\nu}\right)+1200\left(\frac{500}{\nu}\right)\)
\(\Rightarrow C=\frac{375}{4}\nu+\frac{600000}{\nu}\)
(iii). Option : (c)
\(\frac{dC}{dv}\) = \(\frac{375}{4}\) - \(\frac{600000}{v^2}\)
Let \(\frac{dc}{dv}\) = 0
⇒ v2 = \(\frac{600000\times 4}{375}\)= 6400
⇒ v = 80 km/h
(iv). Option : (c)
Fuel cost for running train to travel 500 km at the most economic speed is \(\frac{375}{4}v\)
= \(\frac{375}{4}\) x 80
= Rs. 7500/−
(v). Option : (d)
Total cost for running 500 km = \(\frac{375}{4}v\) + \(\frac{600000}{v}\)
= \(\frac{375\times 80}{4}\)+\(\frac{600000}{v}\)
= Rs.15000/−