Question

An electric kettle is rated at `230 V, 1000 W`. What is the resistance of its element ? What maximum current can pass through its element ?

Answer 1

Correct Answer - `52.9 Omega, 4.35 A`
As `P = (V^2)/( R), R = (V^2)/(P) = ((230 V)^2)/(1000 W) = 52.9 Omega`
Further, `I = (V)/( R) = (230 V)/(52.9 Omega) = 4.35 A`.