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What is the minimum resistance which can be made using five resistors each of `(1//5) Omega` ?
A. `(1//5) Omega`
B. `(1//25) Omega`
C. `(1//10) Omega`
D. `25 Omega`

1 Answer

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Correct Answer - B
Minimum resistance is obtained in parallel combination. Thus, `R_p = ((1//5 Omega))/(5) = (1//25) Omega`.

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