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A ray of light is incident on a glass slab at an angle of `45^(@)`. If refractive index of glass be 1.6, what is the angle of refraction ?

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Correct Answer - `26.2^(@)`
Here, `i= 45^(@), .^(a)n_(g) = 1.6 , r = ?`
From `.^(a)n_(g) = (sini)/(sinr), sinr = (sini)/(.^(a)n_(g)) = (sin45^(@))/(1.6) = (1//sqrt2)/(1.6) = 0.4418`
Using tables of natural sines, `r = 26.2^(@)`

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