Since both the wires are made of the same material and have equal lengths and equal diameters, these have the same resistance. Let it be `R`.

When connected in series , their equivalent resistance is given by

`R_s = R + R = 2 R`

When connected in parallel, their equivalent resistance is given by

`(1)/(R_p) = (1)/( R) + (1)/( R) = (2)/(R)` or `R_p = (R )/(2)`

Further, electrical power is given by `P = (V^2)/( R)`

Power (or heat produced) in series, `P_s = (V^2)/(R_s)`

Power (or heat produced) in parallel, `P_p = (V^2)/(R_p)`

Thus, `(P_s)/(P_p) = (V^2//R_s)/(V^2//R_p) = (R_p)/(R_s) = (R//2)/(2 R) = (1)/(4)` or `P_s : P_p : : 1 : 4`

Thus, (c) is the correct answer.