Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
399 views
in Physics by (71.8k points)
closed by
A 1.5 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 15 cm. Distance of object from the lens is 20 cm. Use lens formula to find the nature, position and size of the image.

1 Answer

0 votes
by (72.0k points)
selected by
 
Best answer
`h_(1)= +1.5 cm, f= +15 cm, u = -20 cm`
As we know, `(1)/(f)=(1)/(v)-(1)/(u)rArr(1)/(v)=(1)/(f)+(1)/(u)`
`(1)/(v)=(1)/((+15))+(1)/((-20))=(1)/(15)-(1)/(20)=+(1)/(60)" "therefore" "v = +60 cm`
Now, `(h_(2))/(h_(1))=(v)/(u) rArr h_(2) = (v xx h_(1))/(u)=(+60 xx 1.5)/(-20) = -4.5 cm`
Nature : Real and inverted.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...