Here, `h_(1) = 1.2 m`, `f = -20 cm`

`v = -60 cm`, `u = ? h_(2) =?`

From mirror formula

`1/v + 1/u = 1/f`

`1/u = 1/f - 1/v = 1/(-20) + 1/60 = -1/30`

`u = -30 cm`

Therefore the object is to be held at 30 cm in front of the mirror.

As `h_(2)/h_(1) = (-v)/u = 60/(-30) = 2`

`:. h_(2) = -2h_(1) = -2 xx 1.2 m = -2.4 m`

Negative sign represents inverted image.