`R_(1)= 5 Omega , R_(2) = 8Omega , R_(3) =12Omega `
Resultant resistance , ` R= R_(1) + R_(2) + R_(3)` (series)
R = 5 + 8+ 12 = 25 `Omega `
V = IR
` I = V/R = 6/25 = 0.24 A `
Reading in ammeter is 0.24A
` R_(3) = 12 Omega`
` I_(3) = 0.24 A ` " " ...[ I_(1) = I_(2) = I_(3) =I`
` V_(3) = ? Rightarrow V_(3) = I_(3) xx R_(3) = 0.24 xx 12 = 2.88` Volts