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Find the area of the minor segment of a circle of radius 14 cm, when the angle of the corresponding sector is 60°.

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Solution:

Given that, radius of circle (r) = 14 cm

and angle of the corresponding sector i.e., central angle (θ) = 60°

Since, in ΔAOB, OA = OB = Radius of circle i.e., ΔAOB is isosceles.

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