Correct answer is: (4) (1, 3)
ß = \(\lim\limits_{x\to 0}(cos x)^{cot x}\)
= Exp {\(\lim\limits_{x\to 0}\frac{cos x-1}{tan x}\)} (0/0 type)
= Exp{\(\lim\limits_{x\to 0}\frac{-sin x}{sec^2x}\)} (By using D.L.H. Rule)
= Exp{\(\frac{-sin 0}{sec^20}\)}
= Exp{0} = e0 = 1
\(\therefore\) ß = 1
α = –4 ; β β = 1
If ax2 + bx – 4 = 0 are the roots then
6a – 4b – 4 = 0 & a + b – 4 = 0
⇒ a = 1 & b = 3