Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
11.6k views
in Physics by (35.0k points)

At very high frequencies, the effective impendance of the given circuit will be ______ Ω.

Please log in or register to answer this question.

2 Answers

+2 votes
by (31.4k points)

Correct answer is 2.

XL = 2πfL

f is very large

\(\therefore\) XL is very large hence open circuit.

\(X_c = \frac{1}{2\pi fC}\)

f is very large.

\(\therefore\) XC is very small, hence short circuit.

Final circuit

+1 vote
by (25 points)
edited by

For ω→∞
1ωC→0⇒1→0⇒ capacitance acts as short circuit
& ωL→∞L→∞ Inductance acts as open circuit
image
Z=2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...