Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
71 views
in Physics by (66.5k points)
closed by
An electric iron of resistance `20 Omega` takes a current of `5 A`. Calculate the heat developed in `30 s`.

1 Answer

0 votes
by (67.7k points)
selected by
 
Best answer
Here, Current, `I = 5A`
Resistance, `R = 20 Omega`
And, Time, `t = 30s`
Now, Heat produced, `H = I6(2) xx R xx t`
`H = (5)^(2) xx 20 xx 30`
`H = 25 xx 20 xx 30`
`H = 15000 J`
Thus, the heat developed is 15000 joules.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...