Correct Answer - A
Let X denote the number of shots in which a markshman hit a target in 10 shots. Then, the probability of r hits is given by
`-P(X=r)=.^10C_r((1)/(5))^r((4)/(5))^10-r`
`therefore` Required Probability `P(X=ge1)=1-P(X=0)`
`=1-.^10C_0((1)/(5))^0((4)/(5))^10=1-((4)/(10))^10`.