LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
35 views
in Probability by (70.2k points)
closed by
The mean and variance of a random variable X having a binomial distribution are `4 and 2` respectively. The `P(X=1)` is
A. `1//4`
B. `1//32`
C. `1//16`
D. `1//8`

1 Answer

0 votes
by (70.7k points)
selected by
 
Best answer
Correct Answer - B
Let n and p be the parameters of the binomial distribution.
We have,
Mean `=4` and Variance `=2`
`rArr np=4 and npq=2`
`rArr p=1//2 =q and n=8`
`therefore` Required Probability `=P(X-1)=.^8C_(1)((1)/(2))^1((1)/(2))^7=(1)/(32)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...