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How many 6-digit numbers can be formed by using the digits 4, 5, 0, 3, 4, 5?

1 Answer

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by (70.4k points)
 
Best answer
Correct Answer - 150
Required number of numbers `={(6!)/((2!)xx(2!))-(5!)/((2!)xx(2!))}=(180-30)=150.`

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