Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
113 views
in Sets, Relations and Functions by (71.0k points)
closed by
Let `A={1,2},B={3,4}" and "C={4,5}.`
We have
verify that `(AxxB)xxC=Axx(BxxC)` and hence find `AxxBxxC.

1 Answer

0 votes
by (70.4k points)
selected by
 
Best answer
We have
`AxxB={1,2}xx{3,4}={(1,3),(1,4).(2,3),(2,4)}`
`implies" "(AxxB)xxC={(1,3),(1,4),(2,3),(2,4)}xx{4,5}`
`={(1,3,4),(1,3,5),(1,4,4),(1,4,5),(2,3,4),(2,3,5),(2,4,4),(2,4,5)}.`
Again, `BxxC={3,4}xx{4,5}={(3,4),(3,5),(4,4),(4,5)}`
`implies" "Axx(BxxC)={1,2}xx{(3,4),(3,5),(4,4),(4,5)}`
`={(1,3,4),(1,3,5),(1,4,4),(1,4,5),(2,3,4),(2,3,5),(2,4,4),(2,4,5)}.`
`:." "(AxxB)xxC=Axx(BxxC)=AxxBxxC.`
Hence, `(AxxBxxC)={(1,3,4),(1,3,5),(1,4,4),(1,4,5),(2,3,4),(2,3,5),(2,4,4),(2,4,5)}.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...