Correct Answer - B
We have
`f(x)=log_(x^(2)) 25=log_(x^(2)) 5^(2)=(2)/(2)log_(x)5=log_(x)5=g(x)`
for all x in their common domain.
Now, `D_(1)="Domain of f"=R-{0,-1,1}`
`and D_(2)="Domain of g"={x:x gt 0, x ne 1}`
`therefore D_(1) nn D_(2)={x:x gt 0, x ne 1}`
`"Thus", f(x)=g(x)"for all" x in {x:x gt 0, xne1}`