Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
154 views
in Logarithm by (71.0k points)
closed by
Evaluate `root(7)(0.00003587)`.

1 Answer

0 votes
by (70.4k points)
selected by
 
Best answer
Let `x = root(7)(0.00003587).` Then,
log `x = 1/7` log (0.00003587)
`= 1/7 (bar(5).5548) = 1/7 (-5 + 0.5548)`
`= 1/7 (-4.4452) = -0.6350`
` = -1 + (1 - 0.6350) = bar(1).3650`
`rArr` x = antilog `(bar(1).3650) = 0.2317.`
Hence, the required value is 0.2317.

Related questions

0 votes
1 answer
asked Sep 11, 2021 in Logarithm by TanujKumar (71.0k points)
0 votes
1 answer
0 votes
1 answer
asked Jan 6, 2022 in Logarithm by Apsha (25.1k points)
0 votes
1 answer
asked Jan 6, 2022 in Logarithm by Apsha (25.1k points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...