First we arrange score in the ascending order.
Then, scores are ` : 34,38, 42,44,46,48, 54,55,63,70`
As there are `10` terms in this data,
so, median will be the mean of fifth and sixth term.
`:.` Median `= (46+48)/2 = 47`
Now, deviation from median for each value,
`d_i = 13,9,5,3,1,1,7,8,16,23.`
`:.` Required Mean deviation `= (sum d_i)/10 = 86/10 = 8.6`
