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If `cosx = -sqrt15/4` and `pi/2 < x < pi`, find the value of `sinx`

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If `cosx = -sqrt15/4` and `pi/2 < x < pi`, find the value of `sinx`
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`sin^x+cos^2x=1`
`sin^2x=1-cos^2x`
`=1-(sqrt15/4)^2`
`=1-15/16=1/16`
`sinx=pm1/4`
`sinx=1/4`.
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