Question

State in each case whehter ` A sub B or A cancel(sub)B`.
(i) `A={0,1,2,3} ,B={1,2,3,4,5}`
`(ii) A=phi, B ={0} `
`(iii) A= {1,2,3} , B= {1,2,4}`
`(iv) A ={x:x in Z, x^2=1}, B={x:x in N X^2=1}`
(v) ` A= {x:x " is a even natural number "},B={x:x " is a integer " }`
(vii) `A={x:x " is a real number "}, B= {x:x " is a complex number"}`
`(viii) A={x :x " is an isosceles triangle in a planel,
`B={x:x " is an equilateral triangle in the same plane "}`
`(ix) A={x:x " is a square in a plane "}`
`B={x:x " is a rectangle in the same plane "}`
` (x) A={x:x " is a triangle in a plane "}`,
` B=(x:x " is a rectangle in the same plane"}`,
`(xi) A={x:x " is an even natural number less than " 8}`
`B={x:x " is a natural number which divides" 32}`.

Answer 1

Correct Answer - (i) `A cancel(sub) B`
(ii) `Asub B`
(iii) ` A cancel(sub)B`
(iv) `A cancel (sub) B`
(v) ` A sub B`
(vi) `A sub B`
(vii) ` A sub B`
(viii) ` A cancel(sub) B `
(ix) ` A sub B `
(x) `A cancel(sub) B`
(xi) `A cancel (sub) B`
(iv) `A= {-1, 1} and B ={1} `. So, ` A cancel(sub)B`.
(v) `A={2, 4,6,8.....} and B ={ ...., -1, 0,1,2,3,4,5,6,7,8......]`So, ` AsubB`.
(vi) Every integer is a rational number.
(vii) We may write a real number x as `x ^+0i`.
So, every real number is a complex number.
(ix) Every square is a rectangle.
(xi) `A={2,4,6} and B={1,2,4,8, 16,32}` So, `A cancel(sub) B`.