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There are 10 seats in the first row of a theater of which 4 are to be occupied. The number of ways of arranging 4 person so that no two persons sit side by side is :

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Best answer
`10->4->6`
`7C_4*4!`
`=(7!)/(3!*4!)*4!`
`=7*6*5*4`
`7C_3*3!*4`
option B,C,D are correct.

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