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If `A={x : x=2n+1, n in Z} a n d B={x : x=2n , n in Z}` , then `AuuB=?`

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If `A={x : x=2n+1, n in Z} a n d B={x : x=2n , n in Z}` , then `AuuB=?`
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We have ,
`A cup B= { x :x " is an odd integer" } cup {x :x " is an even integer} `
`={x:x " is an integer "=Z`.
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