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Find the extremities of latus rectum of the parabola `y=x^2-2x+3`.

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Find the extremities of latus rectum of the parabola `y=x^2-2x+3`.
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`y=x^2-2x+3`
`y=(x-1)^2+2`
`(x-1)^2=y-2`
`(h-1)^2=(9/4-2)`
`(h-1)^2=1/4`
`h-1=pm1/2`
`h=1/2,3/2`
Latus Rectum=`(1/2,9/4) and(3/2,9/4)`.
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