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If A(0,0),B(0, 3) and C(4,0) are the vertices at triangle then equation of internal bisector of `/_B` is given by:

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Equation of BC
`x/4+y/3=c`
`3x+4y=12`
Equation of AB
x=0
`(3x+4y-12)/sqrt(3^2+4^2)=pmx`
`(3x+4y-12)/5=pmx`
after taking both the cases
`x-2y+6=0`
`2x+y-3=0`.

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