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in Continuity and Differentiability by (35.0k points)
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Find the value of k, if the function

h(x) = x2 + 1, for x < 0

\(=5\sqrt{x^2 + 1} + k,\) for x ≥ 0

is continuous at x = 0

1 Answer

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Best answer

h(x) = x2 + 1, for x < 0

Given, h is continuous at x = 0

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