f(x) = (1 - sin x)/(π - 2x)^2, for x ≠ π/2,

Question

If \(f(x) = \frac{(1 - sin\,x)}{(\pi - 2x)^2},\) for x ≠ \(\frac{\pi}{2},\) is continuous

at x = \(\frac{\pi}{2},\) then find \(f\left(\frac{\pi}{2}\right).\)

f(x) = (1 - sin x)/(π - 2x)², for x ≠ π/2,

Answer 1

f(x) = (1 - sin x)/(π - 2x)²

Given, f is continuous at x = \(\frac{\pi}{2}\)