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CH3CH2COO^– Na^+ NaOH,+? → + Heat CH3CH3 + Na2CO3. Consider the above reaction

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in Chemistry by (35.0k points)
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CH3CH2COO– Na+ \(\overset{NaOH,\,+?}{\underset{Heat}{\longrightarrow}}\) CH3CH3 + Na2CO3.

Consider the above reaction and identify the missing reagent/chemical.

(1) B2H6

(2) Red Phosphorus

(3) CaO

(4) DIBAL-H

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1 Answer

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Correct answer is (3).

Decarboxylation takes place by soda-lime

(NaOH + CaO)

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