Correct option is (4) 4v
Escape velocity from the Earth's surface,
\(v_e = \sqrt{\frac{2GM}R}\)
\(= \sqrt{\frac{2G[\rho \times (4\pi R^3/3)]}{R}}\)
\(= \sqrt{\frac{8G\rho \pi R^2}3}\)
∴ ve ∝ R (For same density)
\(\frac{v_1}{v_2} = \frac{R_1}{R_2}\)
⇒ \(\frac v{v_2} = \frac R{4R}\)
∴ v2 = 4v