Correct option is (1) 41.5 kJ/mol
Arrhenius equation
k = Ae−Ea/RT
ln k = ln A + ln e−Ea/RT
ln k = ln A − \(\frac{E_a}R (\frac 1T)\) .......(1)
Slope of ln k vs \(\frac 1T\) curve,
m = \(- \frac{E_a}R\)
−5 × 103 = \(- \frac{E_a}R\)
Ea = 5 × 103 × 8.314 J/mol
= 41.57 × 103 J/mol
= 41.5 kJ/mol