Correct option is (1) 60 cm
From the application of potentiometer to compare two cells of emfs E1 and E2 by balancing lengths l1 and l2.
\(\frac{E_1}{E_2} = \frac{l_1}{l_2}\)
⇒ \(l_2 = l_1\left(\frac{E_2}{E_1}\right)\)
\(= 36 \left(\frac{2.5V}{1.5V}\right)\)
\(= 60 \) cm