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उस वृत्त का समीकरण ज्ञात कीजिए जो बिंदु `(2, 4)` से होकर जाता है तथा जिसका केंद्र रेखाओं `x-y=4` तथा `2x+3y=-7` का प्रतिच्छेदन बिंदु है।

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Correct Answer - `x^(2)+y^(2)-2x+6y-40=0`
दी गई समीकरण को हम करने पर,
त्रिज्या `=sqrt((1-2)^(2)+(-3-4)^(2))=sqrt(50)`
`:.` वृत्त का अभीष्ट समीकरण, `(x-1)^(2)+(y+3)^(2)=(sqrt(50))^(2)`

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