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मान ज्ञात कीजिए sinx+sin2x+sin3x=cosx+cos2x+cos3x`

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Correct Answer - `(i) (1)/(8)(4n+1)pi, 2n pi+- (2pi)/(3), n in I " " (ii) n=(npi)/(4), (2n+1) (pi)/(24), n in I`

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